switching to high quality piper tts and added label translations

2026-01-29 23:48:19 +01:00
commit d80c619df9
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+from collections import defaultdict
+
+from sympy.utilities.iterables import multiset, is_palindromic as _palindromic
+from sympy.utilities.misc import as_int
+
+
+def digits(n, b=10, digits=None):
+    """
+    Return a list of the digits of ``n`` in base ``b``. The first
+    element in the list is ``b`` (or ``-b`` if ``n`` is negative).
+
+    Examples
+    ========
+
+    >>> from sympy.ntheory.digits import digits
+    >>> digits(35)
+    [10, 3, 5]
+
+    If the number is negative, the negative sign will be placed on the
+    base (which is the first element in the returned list):
+
+    >>> digits(-35)
+    [-10, 3, 5]
+
+    Bases other than 10 (and greater than 1) can be selected with ``b``:
+
+    >>> digits(27, b=2)
+    [2, 1, 1, 0, 1, 1]
+
+    Use the ``digits`` keyword if a certain number of digits is desired:
+
+    >>> digits(35, digits=4)
+    [10, 0, 0, 3, 5]
+
+    Parameters
+    ==========
+
+    n: integer
+        The number whose digits are returned.
+
+    b: integer
+        The base in which digits are computed.
+
+    digits: integer (or None for all digits)
+        The number of digits to be returned (padded with zeros, if
+        necessary).
+
+    See Also
+    ========
+    sympy.core.intfunc.num_digits, count_digits
+    """
+
+    b = as_int(b)
+    n = as_int(n)
+    if b < 2:
+        raise ValueError("b must be greater than 1")
+    else:
+        x, y = abs(n), []
+        while x >= b:
+            x, r = divmod(x, b)
+            y.append(r)
+        y.append(x)
+        y.append(-b if n < 0 else b)
+        y.reverse()
+        ndig = len(y) - 1
+        if digits is not None:
+            if ndig > digits:
+                raise ValueError(
+                    "For %s, at least %s digits are needed." % (n, ndig))
+            elif ndig < digits:
+                y[1:1] = [0]*(digits - ndig)
+        return y
+
+
+def count_digits(n, b=10):
+    """
+    Return a dictionary whose keys are the digits of ``n`` in the
+    given base, ``b``, with keys indicating the digits appearing in the
+    number and values indicating how many times that digit appeared.
+
+    Examples
+    ========
+
+    >>> from sympy.ntheory import count_digits
+
+    >>> count_digits(1111339)
+    {1: 4, 3: 2, 9: 1}
+
+    The digits returned are always represented in base-10
+    but the number itself can be entered in any format that is
+    understood by Python; the base of the number can also be
+    given if it is different than 10:
+
+    >>> n = 0xFA; n
+    250
+    >>> count_digits(_)
+    {0: 1, 2: 1, 5: 1}
+    >>> count_digits(n, 16)
+    {10: 1, 15: 1}
+
+    The default dictionary will return a 0 for any digit that did
+    not appear in the number. For example, which digits appear 7
+    times in ``77!``:
+
+    >>> from sympy import factorial
+    >>> c77 = count_digits(factorial(77))
+    >>> [i for i in range(10) if c77[i] == 7]
+    [1, 3, 7, 9]
+
+    See Also
+    ========
+    sympy.core.intfunc.num_digits, digits
+    """
+    rv = defaultdict(int, multiset(digits(n, b)).items())
+    rv.pop(b) if b in rv else rv.pop(-b)  # b or -b is there
+    return rv
+
+
+def is_palindromic(n, b=10):
+    """return True if ``n`` is the same when read from left to right
+    or right to left in the given base, ``b``.
+
+    Examples
+    ========
+
+    >>> from sympy.ntheory import is_palindromic
+
+    >>> all(is_palindromic(i) for i in (-11, 1, 22, 121))
+    True
+
+    The second argument allows you to test numbers in other
+    bases. For example, 88 is palindromic in base-10 but not
+    in base-8:
+
+    >>> is_palindromic(88, 8)
+    False
+
+    On the other hand, a number can be palindromic in base-8 but
+    not in base-10:
+
+    >>> 0o121, is_palindromic(0o121)
+    (81, False)
+
+    Or it might be palindromic in both bases:
+
+    >>> oct(121), is_palindromic(121, 8) and is_palindromic(121)
+    ('0o171', True)
+
+    """
+    return _palindromic(digits(n, b), 1)